SOLUTION MANUAL FOR GENETICS FROM GENES TO GENOMES, 7TH EDITION, MICHAEL GOLDBERG, JANICE FISCHER, LEROY HOOD, LELAND HARTWELL

SOLUTION MANUAL

FOR GENETICS

FROM GENES TO

GENOMES, 7TH

EDITION, MICHAEL

GOLDBERG, JANICE

FISCHER, LEROY

HOOD, LELAND

HARTWELL

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Copyright © 2021 McGraw-Hill Education. All rights reserved. No reproduction or distribution without the prior

written consent of McGraw-Hill Education.

 chapter 1

Mendel’s Principles of Heredity

Synopsis

Chapter 1 covers the basic principles of inheritance that can be summarized as Mendel’s Laws of

Segregation (for one gene) and Independent Assortment (for more than one gene).

Key terms

genes and alleles of genes – A gene determines a trait, and different alleles or forms of a

gene exist. The color gene in peas has two alleles: yellow and green.

genotype and phenotype – Genotype is the genetic makeup of an organism (written as

alleles of specific genes), while phenotype is how the organism looks.

 homozygous and heterozygous – When both alleles of a gene are the same, the

individual is homozygous for that gene (or pure breeding). If the two alleles are

different, the organism is heterozygous (also called a hybrid).

dominant and recessive – The dominant allele is the one that controls phenotype in the

heterozygous genotype; the recessive allele controls phenotype only in a homozygote.

monohybrid or dihybrid cross – a cross between individuals who are both heterozygotes

for one gene (monohybrid) or for two genes (dihybrid).

testcross – performed to determine if an individual with the dominant characteristic is

homozygous or heterozygous: An individual with the dominant phenotype but

unknown genotype is crossed with an individual with the recessive phenotype.

Key ratios

3:1 – Ratio of progeny phenotypes in a cross between monohybrids

 [Aa × Aa → 3 A– (dominant phenotype) : 1 aa (recessive phenotype)]

1:2:1 – Ratio of progeny genotypes in a cross between monohybrids

 (Aa × Aa → 1 AA : 2 Aa : 1aa)

1:1 – Ratio of progeny genotypes in a cross between a heterozygote and a recessive homozygote

 (Aa × aa → 1 Aa : 1aa)

1:0 – All progeny are the same phenotype. Can result from either of two cases:

 [AA × – – → A– (all dominant phenotype)]

[aa × aa → aa (all recessive phenotype)]

9:3:3:1 – Ratio of progeny phenotypes in a dihybrid cross

 (Aa Bb × Aa Bb → 9 A– B– : 3 A– bb : 3 aa B– : 1 aa bb)

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chapter 1

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Copyright © 2021 McGraw-Hill Education. All rights reserved. No reproduction or distribution without the prior

written consent of McGraw-Hill Education.

Problem Solving

The essential component of solving most genetics problems is to DIAGRAM THE CROSS in a

consistent manner. Usually you will be given information about phenotypes, so the diagram would

be:

Phenotype of one parent × phenotype of the other parent → phenotype(s) of progeny

The goal is to assign genotypes to the parents and then use these predicted genotypes to generate

the genotypes, phenotypes, and ratios of progeny. If the predicted progeny match the observed

data you were provided, then your genetic explanation is plausible.

The points listed below will be particularly helpful in guiding your problem solving:

• Remember that two alleles of each gene exist when describing the genotypes of

individuals. But if you are describing gametes, remember that only one allele of each

gene is in a gamete.

• You will need to determine whether a character is dominant or recessive. Two main

clues will help you answer this question.

o First, if the parents of a cross are true breeding for the alternative characters of the

trait, look at the phenotype of the F1 progeny. Their genotype must be

heterozygous, and their phenotype is thus determined by the dominant allele of

the gene.

o Second, look at the F2 progeny (that is, the progeny of the F1 hybrids). The 3/4

portion of the 3:1 phenotypic ratio indicates the dominant character.

• You should recognize the need to set up a testcross (to establish the genotype of an

individual showing the dominant character by crossing this individual to a homozygote

for the recessive allele).

• You must keep in mind the basic rules of probability:

o Product rule: If two outcomes must occur together as the result of independent

events, the probability of one outcome AND the other outcome is the product of

the two individual probabilities.

o Sum rule: If there is more than one way in which an outcome can be produced,

the probability of one OR the other occurring is the sum of the two mutually

exclusive individual probabilities.

• Be aware that sometimes you need to use conditional probability, meaning that an

event’s probability is influenced by its relationship to another event that has already

occurred. You were introduced to conditional probability in Solved Problem III in this

chapter, and several of the problems in Section 1.3 require this kind of thinking. For

example, suppose you are given a pedigree diagram for a disease caused by a recessive

allele. You are asked to determine the chance that an unaffected individual is a carrier

(Dd), when both parents are carriers. As the cross that produced the unaffected

individual is Dd × Dd, you would expect the chance of a Dd child to be 1/2. This is true,

but it was not the question you were asked! You know something about the individual in

question—which is that they are unaffected—they cannot be dd. This means that in this

case, the 1 DD : 2 Dd : 1 dd ratio changes to 1 DD : 2 Dd, and the chance is 2/3 that the

unaffected individual is a carrier. When solving probability problems in pedigrees,

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Version 2021
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Pages 19
Language English
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